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A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of Aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge and brought in contact, the 45 th division coincides with the main scale line and that the zero of the main scale is barely visible. What is the thickness of the sheet if the main scale reading is 0.5 mm and the 25th division coincides with the main scale line?

Options

A.0.75 mm
B.0.80 mm
C.0.70 mm
D.0.50 mm

Correct Answer

A. 0.75 mm

Exam
JEE Main
Language
English
Year
2016
Difficulty
1/5
Section
Physics

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