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Electrons of mass (m) with de-Broglie wavelength (\lambda) fall on the target in an (X) ray tube. The cutoff wavelength ((\lambda_{0})) of the emitted X-ray is :-

\lambda_{0} = \frac{2mc\lambda_{2}}{h}

\lambda_{0} = \mathrm{mc}

\lambda_0 = \frac{2\mathrm{m}^{2}\mathrm{c}^{2}}{\mathrm{h}^{2}}\lambda^{3}

\lambda_{0} = \lambda

C. \(\lambda0 = \frac{2\mathrm{m}^{2}\mathrm{c}^{2}}{\mathrm{h}^{2}}\lambda^{3}\)

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