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( \mathrm { AlF } _ { 3 } ) is soluble in HF only in presence of KF . It is due to the formation of

Options

A.K3[AlF3H3]\mathrm { K } _ { 3 } \left[ \mathrm { AlF } _ { 3 } \mathrm { H } _ { 3 } \right]
B.K3[AlF6]\mathrm { K } _ { 3 } \left[ \mathrm { AlF } _ { 6 } \right]
C.AlH3\mathrm { AlH } _ { 3 }
D.K[AlF3H]\mathrm { K } \left[ \mathrm { AlF } _ { 3 } \mathrm { H } \right]

Correct Answer

A. \( \mathrm { K } { 3 } \left[ \mathrm { AlF } { 3 } \mathrm { H } { 3 } \right] \)

Exam
NEET
Language
English
Year
2016
Difficulty
1/5
Section
Chemistry

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