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The correct geometry and hybridization for XeF4 are :

Options

A.Octahedral, \( \mathrm { sp } ^ { 3 } \mathrm {~d} ^ { 2 } \)
B.Trigonal bipyramidal, \( \mathrm { sp } ^ { 3 } \mathrm {~d} \)
C.Planar triangle, \( \operatorname { sp } ^ { 3 } d ^ { 3 } \)
D.Square planar, \( \mathrm { sp } ^ { 3 } \mathrm {~d} ^ { 2 } \)

Correct Answer

A. Octahedral, \( \mathrm { sp } ^ { 3 } \mathrm {~d} ^ { 2 } \)

Exam
NEET
Language
English
Year
2016
Difficulty
1/5
Section
Chemistry

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