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A satellite of mass (m) is orbiting the Earth (of radius (R)) at a height (h) from its surface. The total energy of the satellite in terms of (\mathrm{g}_{0}), the value of acceleration due to gravity at the Earth's surface, is

Options

A.(0)2R+h\frac{(0)}{2R+h}
B.\mathrm{mg}\mathrm{R}_{2}\) \(\frac{0}{(\quad)}
C.2mgR20\underset{0}{2mg\mathrm{R}^{2}}
D.2,gR20-\frac{2,g\mathrm{R}^{2}}{0}

Correct Answer

B. \(\mathrm{mg}\mathrm{R}{2}\) \(\frac{0}{(\quad)}\)

Exam
NEET
Language
English
Year
2016
Difficulty
1/5
Section
Physics

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